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View Full Version : Anti-Superman Team Ability Loophole?


SpideyGoNuts
03/12/2003, 06:23
Hey all! I'm new here so be gentle and don't slip any roofies into my drink. Thanks, much appreciated. ;)

Okay! My question is the topic of debate night after night of Heroclix and my next team idea basically hangs on the answer.

(And I just realized that after posting this on the Marvel Forum, that this DC forum actually even exists here. Opps. That said, I'll just pot this here though I'm uncertain if its already been discussed or not!)

The Anti-Superman Team Ability states:
"If two Superman Enemies are adjacent, the figure with the highest point value has the Outwit super power. If that figure already has Outwit, this special ability does not work. "

That said, lets say I've got ohhh....

A - R Doomsday (137pts)
B - E Brainiac 13 (122pts)
C - R Intergang Agent (18pts)
D - V Intergang Agent (25pts)

Now lets say all of them are cozied up nice and tight in a square two by two.
Ex:

A.B.
C.D.

Because they all have varying point values and they are all adjacent, can I then:

1 - First declare R Agent and V Agent as a group of two which are adjacent, to give the V Agent outwit, and then...

2 - Declare V Agent and E Brainiac 13 as a group of two which are adjacent, thus giving E Brainiac 13 Outwit, and then...

3 - Declare E Brainiac 13 and R Doomsday as a group of two which are adjacent, thus giving R Doomsday Outwit?

I assume I can given the fact you can chain the Defender's team abilty in even a straight line of figures
(Ex: X.A.B.CX. )where Fig. A shares its defense of 18 with Fig. B, changing his defense of 15 to said 18 and then Fig. C can share Fig. B's new 18 defense value, completing the chain.

I know this is longwinded and thankyou for bearing with me here, just thought I'd lay it out as clear as possible.

Thanks!

absalom_daak
03/12/2003, 07:05
Even better try 3 R Intergang Agents @18 each, call them X, Y and Z.

Arrange them so they're all standing next to each other
e.g.

XY
Z

Then X and Y are a pair and you can choose to give outwit to either one as they are both the same number of points. So let's say we give it to X.

X and Z are a pair. This time we'll give it to Z.

Y and Z are a pair, so this time we'll give it to Y.

Thus for 3*18=54 points you get 3 lots of outwit.

Shame that the guys are pretty useless for almost anything else.

For an extra 6 points you could make them R Intergang Medics, and if you're playing mixed then you could add a R Invisible Girl to give them a bit of a chance (Total Cost - 97 points).

However it is a formation that does seem to say 'energy explosion' in large friendly letters.

And it ain't terribly manoeuvrable.

Now using Doombots might be another story.

SpideyGoNuts
03/12/2003, 08:29
Right on :)

Thanks for the reply!

And you're right, its not very maneuverable or practical but at least I can get 3 seperate instances of outwit for 54 points. Also, it ends a much debated discussion.

Of course, all of this assuming that it is in fact legal to chain them all together like that.

Thanks again!

Tsannik
03/12/2003, 08:49
You two pretty much have the jist of this team ability down. There actually is no loophole here as this is how it was intended to be used.

There are somethings that need to be remembered, though.

Both Superman Enemy people (if wildcard based) must stay Superman enemy in order for the Outwit to stay.

So, if you Outwit, then change your team membership to Defenders, that outwit is lost. Even if you change back to Superman Enemy. There are some other stipulations, but we'll not go into that yet.

SLAYER X
03/12/2003, 16:40
That's cool I was about to ask the same thing except with this senario. I am using a intergang medic on my team can I use outwit from dr.doom more than once sice he is surrounded by people who cost less, here is my example-
A-dr. doom
BC&D- doombots...and it looks like this

AB
CD
Now in that formation can dr.doom use the team ability seperately from all 3 so he outwits 3 people and then each doombot would ally with the other 2 causeing them to get to outwit 2 more people each? That would be 9 people getting outwitted by just 4.

Tsannik
03/12/2003, 17:05
No. The figure receiving Outwit can only be assigned it once.

If the figure already has Outwit, this team ability has no effect.

The Doombots, assuming they were all equally costed.... would gain three Outwits between themselves as:

B/C is a pair Assign to B
C/D is a pair Assign to C
B/D is a pair Assign to D (Cause B already has)

So the most Outwit you cuold have in that diagram is 4.

SLAYER X
03/12/2003, 17:18
I thought maybe even though it says someone who already has that super power can not get it but since it comes from a team ability and not a superpower I thought that would allow for a loophole.

Tsannik
03/12/2003, 17:23
Yeah, the PAC itself states:

If the figure already has Outwit, this team ability has no effect.

But also, from the FAQ...
The ability grants the Outwit power, so if the above conditions are met, it would be possible for an opposing character to Outwit this newly granted Outwit power.

So, this team ability actually puts the power on the dial itself. It can coexist with other powers EXCEPT an already present Outwit.

This is what allows this granted power to be Outwitted.

SLAYER X
03/12/2003, 17:34
I didn't think there would anyway to get it to come out that way but I thought I may as well ask and see.